[err:数据源标签'PE.DataSource id="cone" datasource="资料_内容页" itemId="929" xslt="true" '返回数据错,原因:行 17 上的开始标记“SoftIntro”与结束标记“SPA”不匹配。 行 26,位置 12。,源码:929 <meta http-equiv="refresh" content="0;url=/Item/929.aspx?wu=1" /> 24游乐场上的翻滚过山车0.00B0.00Botherczwlzx孙新czwlzx/UploadFiles/UserPic/UserAvatars/15219_150_150.jpg <script language="JavaScript" type="text/JavaScript" src="/Common/GetHits.aspx?id=929"></script> <script language="JavaScript" type="text/JavaScript" src="/Common/GetHits.aspx?hitstype=dayhits&id=929"></script> <script language="JavaScript" type="text/JavaScript" src="/Common/GetHits.aspx?hitstype=weekhits&id=929"></script> <script language="JavaScript" type="text/JavaScript" src="/Common/GetHits.aspx?hitstype=monthhits&id=929"></script> <script language="JavaScript" type="text/JavaScript" src="/Common/GetBrowseTimes.aspx?id=929"></script> <img src="/images/star3.jpg" /> 孙新0游乐场,上的,翻滚,过山车上传2004年12月26日/UploadFiles/ckzlzx_UploadFiles_2200/20041226124326360.gif游乐场上的翻滚过山车是一种惊险有趣的游戏。过山车在凌空架起的环形轨道上滑行(如图1-1所示),所以也叫游乐场上的翻滚过山车是一种惊险有趣的游戏。过山车在凌空架起的环形轨道上滑行(如图1-1所示),所以也叫单环滑车。轨道最高处距地面32米,最低处几乎贴地。圆环直径15米。整个滑车由6节小滑车组成,每节小滑车可乘坐4人,每个坐位上配有安全带。从滑车起动到停止仅1分钟时间,就在这短暂的1分钟内使人体验到宇宙飞行的乐趣。   这项游戏是根据力学中的机械能守恒以及圆周运动的知识设计的。人们坐上滑车后,由操纵台控制,首先沿缓坡轨道牵引到32米高处,随后牵引钩和滑车自动脱离,这时滑车就沿轨道从32米高处滑下。当滑车到达圆环顶部时,人会头朝下,看上去相当危险,担心人和车会不会掉下来呀?下面我们用圆周运动和机械能守恒的知 【内容简介】游乐场上的翻滚过山车是一种惊险有趣的游戏。过山车在凌空架起的环形轨道上滑行(如图1-1所示),所以也叫单环滑车。轨道最高处距地面32米,最低处几乎贴地。圆环直径15米。整个滑车由6节小滑车组成,每节小滑车可乘坐4人,每个坐位上配有安全带。从滑车起动到停止仅1分钟时间,就在这短暂的1分钟内使人体验到宇宙飞行的乐趣。   这项游戏是根据力学中的机械能守恒以及圆周运动的知识设计的。人们坐上滑车后,由操纵台控制,首先沿缓坡轨道牵引到32米高处,随后牵引钩和滑车自动脱离,这时滑车就沿轨道从32米高处滑下。当滑车到达圆环顶部时,人会头朝下,看上去相当危险,担心人和车会不会掉下来呀?下面我们用圆周运动和机械能守恒的知识来分析这种游戏的物理原理。   首先我们分析一下当滑车运动到环底和环顶时车中的人的受力情况(如图1-2所示)。图中mg为人所受的重力;N下和N上分别为滑车在底部和顶部时对人的支持力(为使问题简化,可不考虑摩擦及空气阻力)。我们知道,滑车沿圆环滑动,人也在做圆周运动。这时人做圆周运动所需的向心力由mg和N提供。用V下表示人在圆环底部的速度,V上表示人在圆环顶部的速度,R表示环的半径,则 在底部               (1)   在顶部              (2)   因为不考虑摩擦及空气阻力的作用,所以滑车在轨道上各点的机械能守恒。用h表示从高处到环底的高度,根据机械能守恒定律,对底部和顶部而言存在下列关系:       (3)游乐场上的翻滚过山车是一种惊险有趣的游戏。过山车在凌空架起的环形轨道上滑行(如图1-1所示),所以也叫单环滑车。轨道最高处距地面32米,最低处几乎贴地。圆<P>游乐场上的翻滚过山车是一种惊险有趣的游戏。过山车在凌空架起的环形轨道上滑行(如图<SPAN lang=EN-US>1</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">-</SPAN><SPAN lang=EN-US>1</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">所示),所以也叫单环滑车。轨道最高处距地面</SPAN><SPAN lang=EN-US>32</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">米,最低处几乎贴地。圆环直径</SPAN><SPAN lang=EN-US>15</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">米。整个滑车由</SPAN><SPAN lang=EN-US>6</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">节小滑车组成,每节小滑车可乘坐</SPAN><SPAN lang=EN-US>4</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">人,每个坐位上配有安全带。从滑车起动到停止仅</SPAN><SPAN lang=EN-US>1</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">分钟时间,就在这短暂的</SPAN><SPAN lang=EN-US>1</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">分钟内使人体验到宇宙飞行的乐趣。</SPAN> <P class=MsoNormal align=center><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><IMG alt="" hspace=0 src="PE.SiteConfig.ApplicationPathPE.SiteConfig.uploaddir/ckzlzx_UploadFiles_2200/20041226124325734.jpg" align=baseline border=0></SPAN></P> <P class=MsoNormal><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">  这项游戏是根据力学中的机械能守恒以及圆周运动的知识设计的。人们坐上滑车后,由操纵台控制,首先沿缓坡轨道牵引到</SPAN><SPAN lang=EN-US>32</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">米高处,随后牵引钩和滑车自动脱离,这时滑车就沿轨道从</SPAN><SPAN lang=EN-US>32</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">米高处滑下。当滑车到达圆环顶部时,人会头朝下,看上去相当危险,担心人和车会不会掉下来呀?下面我们用圆周运动和机械能守恒的知识来分析这种游戏的物理原理。</SPAN></P> <P class=MsoNormal align=center><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><IMG alt="" hspace=0 src="PE.SiteConfig.ApplicationPathPE.SiteConfig.uploaddir/ckzlzx_UploadFiles_2200/20041226124325580.jpg" align=baseline border=0></SPAN></P> <P class=MsoNormal><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">  首先我们分析一下当滑车运动到环底和环顶时车中的人的受力情况(如图</SPAN><SPAN lang=EN-US>1</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">-</SPAN><SPAN lang=EN-US>2</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">所示)。图中</SPAN><SPAN lang=EN-US>mg</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">为人所受的重力;</SPAN><SPAN lang=EN-US>N</SPAN><SUB><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-size: 10.5pt">下</SPAN></SUB><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">和</SPAN><SPAN lang=EN-US>N</SPAN><SUB><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-size: 10.5pt">上</SPAN></SUB><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">分别为滑车在底部和顶部时对人的支持力(为使问题简化,可不考虑摩擦及空气阻力)。我们知道,滑车沿圆环滑动,人也在做圆周运动。这时人做圆周运动所需的向心力由</SPAN><SPAN lang=EN-US>mg</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">和</SPAN><SPAN lang=EN-US>N</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">提供。用</SPAN><SPAN lang=EN-US>V</SPAN><SUB><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-size: 10.5pt">下</SPAN></SUB><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">表示人在圆环底部的速度,</SPAN><SPAN lang=EN-US>V</SPAN><SUB><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'; mso-bidi-font-size: 10.5pt">上</SPAN></SUB><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">表示人在圆环顶部的速度,</SPAN><SPAN lang=EN-US>R</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">表示环的半径,则</SPAN></P> <P class=MsoNormal style="TEXT-INDENT: 21pt; mso-char-indent-count: 2.0; mso-char-indent-size: 10.5pt"><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">在底部          </SPAN><SPAN lang=EN-US><SUB><?xml:namespace prefix = v ns = "urn:schemas-microsoft-com:vml" /><v:shapetype id=_x0000_t75 coordsize="21600,21600" o:spt="75" o:preferrelative="t" path="m@4@5l@4@11@9@11@9@5xe" filled="f" stroked="f"> <IMG alt="" hspace=0 src="PE.SiteConfig.ApplicationPathPE.SiteConfig.uploaddir/ckzlzx_UploadFiles_2200/20041226124325621.gif" align=baseline border=0></v:shapetype></SUB></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">    (</SPAN><SPAN lang=EN-US>1</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">)</SPAN></P> <P class=MsoNormal><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">  在顶部          <IMG alt="" hspace=0 src="PE.SiteConfig.ApplicationPathPE.SiteConfig.uploaddir/ckzlzx_UploadFiles_2200/20041226124326360.gif" align=baseline border=0></SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">    (</SPAN><SPAN lang=EN-US>2</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">)</SPAN></P> <P class=MsoNormal><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">  因为不考虑摩擦及空气阻力的作用,所以滑车在轨道上各点的机械能守恒。用</SPAN><SPAN lang=EN-US>h</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">表示从高处到环底的高度,根据机械能守恒定律,对底部和顶部而言存在下列关系:</SPAN></P> <P class=MsoNormal style="TEXT-ALIGN: center" align=center><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'"><IMG alt="" hspace=0 src="PE.SiteConfig.ApplicationPathPE.SiteConfig.uploaddir/ckzlzx_UploadFiles_2200/20041226124326371.gif" align=baseline border=0>      (</SPAN><SPAN lang=EN-US>3</SPAN><SPAN style="FONT-FAMILY: 宋体; mso-ascii-font-family: 'Times New Roman'; mso-hansi-font-family: 'Times New Roman'">)</SPA不限 <img src="/UploadFiles/ckzlzx_UploadFiles_2200/20041226124326360.gif" alt="%e6%b8%b8%e4%b9%90%e5%9c%ba%e4%b8%8a%e7%9a%84%e7%bf%bb%e6%bb%9a%e8%bf%87%e5%b1%b1%e8%bd%a6" border="0" /> /UploadFiles/] {PE.Field id="cone" fieldname="Title" /}-初中物理教师网 {PE.Field id="cone" fieldname="gourl" /} {PE.Label id="顶部" currentId="{PE.Field id="cone" fieldname="NodeID" /}"/}

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