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</gourl2><NodeID>1644</NodeID><Title>新人教版八年级物理上册《10.3物体的浮沉条件及其应用(第一课时)》导学案</Title><SoftSize>0.00</SoftSize><SoftSizeUnit>B</SoftSizeUnit><SoftSize>0.00</SoftSize><SoftSizeUnit>B</SoftSizeUnit><typeicon>doc</typeicon><editor>初中物理在线</editor><author>初中物理在线</author><user>初中物理在线</user><userface>PE.SiteConfig.SkinPathMMskin/images/userface.png</userface><Hits>
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   </Stars><Author>初中物理在线</Author><infopoint>1</infopoint><Keyword>物体的浮沉条件及其应用,新人教版八年级物理下册导学案</Keyword><CopyFrom>本站原创</CopyFrom><SoftType></SoftType><CopyrightType></CopyrightType><DecompressPassword></DecompressPassword><OperatingSystem></OperatingSystem><UpdateTime>2013年03月06日</UpdateTime><RegUrl></RegUrl><DemoUrl /><DefaultPicUrl>/UploadFiles/nopic.gif
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				学习目标
				
1.理解物体浮沉的条件.2.会判断物体的浮沉..知识回顾
1.浸在液体中的物体所受的浮</Intro><SoftIntro2>
				学习目标
				
1.理解物体浮沉的条件.2.会判断物体的浮沉..知识回顾
1.浸在液体中的物体所受的浮力,大小等于它________________________.这就是著名的阿基米德原理.用公式表示为F浮=_______=__________.
2.当物体浸没在液体中时,它排开液体的体积等于_________________.即V排=V物
3.当物体漂浮在液面上时,它排开液体的体积等于_________________________.
【自学指导】当把物体浸没在液体中时,物体受到竖直向上的浮力和竖直向下的重力的作用,如图甲所示,是物体浸没在液体中时的受力情况.
当F浮&gt;G物时,物体受到非平衡力的作用,物体上浮,会露出液面一部分体积,最终漂浮在液面上,如图乙所示.漂浮时:F浮=G物
当F浮=G物时,这两个力相互</SoftIntro2><SoftIntro>
    【内容简介】
				学习目标
				
1.理解物体浮沉的条件.2.会判断物体的浮沉..知识回顾
1.浸在液体中的物体所受的浮力,大小等于它________________________.这就是著名的阿基米德原理.用公式表示为F浮=_______=__________.
2.当物体浸没在液体中时,它排开液体的体积等于_________________.即V排=V物
3.当物体漂浮在液面上时,它排开液体的体积等于_________________________.
【自学指导】当把物体浸没在液体中时,物体受到竖直向上的浮力和竖直向下的重力的作用,如图甲所示,是物体浸没在液体中时的受力情况.
当F浮>G物时,物体受到非平衡力的作用,物体上浮,会露出液面一部分体积,最终漂浮在液面上,如图乙所示.漂浮时:F浮=G物
当F浮=G物时,这两个力相互抵消,物体保持原来的静止状态,会悬浮在原来的位置,如图丙所示.悬浮时:F浮=G物
当F浮
另外:物体的重力G物可表示为:G物=ρ物gV物,排开液体的重力G排可表示为G排=ρ液gV排,又因F浮=G排,所以F浮=ρ液gV排,当物体浸没在液体中时,V物=V排,所以:
当F浮>G物时,即ρ液gV排>ρ物gV物,可得出ρ液>ρ物时,物体上浮,最终漂浮在液面上.
当F浮=G物时,即ρ液gV排=ρ物gV物,可得出ρ液=ρ物时,物体悬浮在液体中.
当F浮<ρ物gv物,可得出ρ液><ρ物时,物体下沉,最终沉在底部.>
总结以上可以归纳得出物体浮沉的条件是:浸没在液体中的物体,(1)若G物<ρ液,物体上浮.(2)若g物>F浮或ρ物>ρ液,物体下沉.
典型例题
........
		?
		?
		?</SoftIntro><SoftIntroEncode>
				学习目标
				
1.理解物体浮沉的条件.2.会判断物体的浮沉..知识回顾
1.浸在液体中的物体所受的浮力,大小等于它________________________.这就是著名的</SoftIntroEncode><special /><DownloadUrl>下载地址1|jazx_UploadFiles_352/201303/2013030606225590.doc</DownloadUrl><Content>&lt;p&gt;
				&lt;strong&gt;学习目标&lt;/strong&gt;
				&lt;br /&gt;
1.理解物体浮沉的条件.2.会判断物体的浮沉..&lt;br /&gt;&lt;strong&gt;知识回顾&lt;/strong&gt;&lt;br /&gt;
1.浸在液体中的物体所受的浮力,大小等于它________________________.这就是著名的阿基米德原理.用公式表示为F浮=_______=__________.&lt;br /&gt;
2.当物体浸没在液体中时,它排开液体的体积等于_________________.即V排=V物&lt;br /&gt;
3.当物体漂浮在液面上时,它排开液体的体积等于_________________________.&lt;br /&gt;
【自学指导】当把物体浸没在液体中时,物体受到竖直向上的浮力和竖直向下的重力的作用,如图甲所示,是物体浸没在液体中时的受力情况.&lt;br /&gt;&lt;br /&gt;
当F浮&amp;gt;G物时,物体受到非平衡力的作用,物体上浮,会露出液面一部分体积,最终漂浮在液面上,如图乙所示.漂浮时:F浮=G物&lt;br /&gt;
当F浮=G物时,这两个力相互抵消,物体保持原来的静止状态,会悬浮在原来的位置,如图丙所示.悬浮时:F浮=G物&lt;br /&gt;
当F浮&lt;g物时,物体受到非平衡力的作用,物体下沉,最终沉在底部,并受底部的支持力,如图丁所示.沉到底部时:f浮&gt;&lt;g物&gt;&lt;br /&gt;
另外:物体的重力G物可表示为:G物=ρ物gV物,排开液体的重力G排可表示为G排=ρ液gV排,又因F浮=G排,所以F浮=ρ液gV排,当物体浸没在液体中时,V物=V排,所以:&lt;br /&gt;
当F浮&amp;gt;G物时,即ρ液gV排&amp;gt;ρ物gV物,可得出ρ液&amp;gt;ρ物时,物体上浮,最终漂浮在液面上.&lt;br /&gt;
当F浮=G物时,即ρ液gV排=ρ物gV物,可得出ρ液=ρ物时,物体悬浮在液体中.&lt;br /&gt;
当F浮&lt;g物时,即ρ液gv排&gt;&amp;lt;ρ物gv物,可得出ρ液&amp;gt;&amp;lt;ρ物时,物体下沉,最终沉在底部.&amp;gt;&lt;br /&gt;
总结以上可以归纳得出物体浮沉的条件是:浸没在液体中的物体,(1)若G物&lt;f浮或ρ物&gt;&amp;lt;ρ液,物体上浮.(2)若g物&amp;gt;F浮或ρ物&amp;gt;ρ液,物体下沉.&lt;br /&gt;
典型例题&lt;br /&gt;
........&lt;/f浮或ρ物&gt;&lt;/g物时,即ρ液gv排&gt;&lt;/g物&gt;&lt;/g物时,物体受到非平衡力的作用,物体下沉,最终沉在底部,并受底部的支持力,如图丁所示.沉到底部时:f浮&gt;&lt;/p&gt;
		&lt;p&gt;?&lt;/p&gt;
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