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176(北师大版)2019-2020学年八年级物理同步单元双基双测AB卷:期末模拟卷(B卷提升篇)1.12MB1.12Bdocczwlzx吴晓娟czwlzx/UploadFiles/UserPic/UserAvatars/15219_150_150.jpg
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吴晓娟1(北师大版)2019-2020学年八年级物理同步单元双基双测AB卷,期末模拟卷2020年01月30日/UploadFiles/nopic.gif
一、选择题(每小题2分,共24分)1.(2019·云南初三期末)中华诗词蕴含着丰富的物理知识,以下诗词中有关一、选择题(每小题2分,共24分)1.(2019·云南初三期末)中华诗词蕴含着丰富的物理知识,以下诗词中有关物态变化的分析,正确的是( )A.“斜月沉沉藏海雾”,雾的形成是汽化现象,需要吸热B.“已是悬崖百丈冰”,冰的形成是凝华现象,需要吸热C.“露似真珠月似弓”,露的形成是液化现象,需要放热D.“霜叶红于二月花”,霜的形成是凝固现象,需要放热【答案】C【解析】A.“斜月沉沉藏海雾”,雾是空气中的水蒸气遇冷形成的小水珠,是液化现象,需要放热,故A错误;B.“已是悬崖百丈冰”,冰是水凝固形成的,是凝固现象,需要放热,故B错误;C.“露似真珠月似弓”,露的形成是液化现象,需要放热,故C正确;D.“霜叶红于二月花”
【内容简介】一、选择题(每小题2分,共24分)1.(2019·云南初三期末)中华诗词蕴含着丰富的物理知识,以下诗词中有关物态变化的分析,正确的是( )A.“斜月沉沉藏海雾”,雾的形成是汽化现象,需要吸热B.“已是悬崖百丈冰”,冰的形成是凝华现象,需要吸热C.“露似真珠月似弓”,露的形成是液化现象,需要放热D.“霜叶红于二月花”,霜的形成是凝固现象,需要放热【答案】C【解析】A.“斜月沉沉藏海雾”,雾是空气中的水蒸气遇冷形成的小水珠,是液化现象,需要放热,故A错误;B.“已是悬崖百丈冰”,冰是水凝固形成的,是凝固现象,需要放热,故B错误;C.“露似真珠月似弓”,露的形成是液化现象,需要放热,故C正确;D.“霜叶红于二月花”,霜是空气中的水蒸气遇冷形成的小冰晶,是凝华现象,凝华放热,故D错误。2.(2019·湖南初二期末)如图所示,在一敞口玻璃瓶甲里盛适量的水,使之能浮在一水槽中,将另一只同样的敞口空玻璃瓶乙瓶口朝下,按入槽内水中,并固定位置。在标准大气压下,对槽内水加热到沸腾时( )A.甲、乙瓶中水都能沸腾 B.甲瓶内水不沸腾,乙瓶内水沸腾C.甲瓶内水沸腾,乙瓶内水不沸腾 D.甲、乙瓶中水都不能沸腾【答案】D【解析】因为水在标准大气压下的沸点是100℃,所以槽中水沸腾时温度是100℃,并保持不变。甲瓶中水从槽内水中吸热,温度升高直到100℃,这样甲瓶中的水温也能达到沸点,不过甲瓶中的水一旦与槽内的水温度相等,甲瓶中的水就无法吸热,当然不能沸腾。虽然乙瓶中水温同样可达到100℃,但乙瓶上端封闭,瓶内气压大于标准大气压。因为液体沸点随液面上气压的增大而增大,所以乙瓶中水的沸点高于100℃。这样乙瓶中水温达不到沸点,不能沸腾。故D正确。3.(2019·仪征市第三中学初二期末)如图是在探究甲、乙两种物质质量跟体积关系时作出的图像。则以下分析正确的是( )A.ρ甲>ρ乙 B.ρ甲< ρ乙 C.V甲>V乙 D.m甲=m乙【答案】A【解析】AB.由图可知,当两物体的体积相同时,甲的质量大,根据可知,甲的密度大,故A正确、B错误;CD.题中没有给出甲乙的质量和体积,所以无法进行比较,故CD错误。4.(2019·湖南初二期末)关于物理测量仪器的使用,下列说法正确的是( )A.零刻度线缺失的刻度尺不能用来测量物体的长度B.使用天平测质量时,一定要等指针静止并在分度盘的中央时横梁才算平衡C.所有液体温度计都不能拿离人体读数D.用塑料卷尺测量长度时,若用力拉尺进行测量,那么由此将可能引起测量结果偏小【答案】D【解析】A.刻度尺使用时可以从整刻度开始,零刻度线缺失的刻度尺也能用来测量物体的长度;故A错误;B.当天平指针两边偏转程度相同时,认为天平平衡可以测量天平质量;故B错误;C.体温计是液体温度计,它可以离开人体后再读数;故C错误;D.塑料卷尺本身具有一定的伸缩性,当我们用力拉尺进行测量时,读数会比实际读数偏小;故D正确。一、选择题(每小题2分,共24分)1.(2019·云南初三期末)中华诗词蕴含着丰富的物理知识,以下诗词中有关物态变化的分析,正确的是(   )A.“
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下载地址1|sj/2020/1/2020130102851.rar<p style="line-height: 150%"><strong><span style="font-size:16px;line-height:150%;font-family:宋体">一、选择题(每小题</span></strong><strong><span style="font-size:16px;line-height:150%">2</span></strong><strong><span style="font-size:16px;line-height:150%;font-family:宋体">分,共</span></strong><strong><span style="font-size:16px;line-height:150%">24</span></strong><strong><span style="font-size:16px;line-height:150%;font-family:宋体">分)</span></strong></p><p style="line-height: 150%;vertical-align: middle"><strong>1</strong><strong><span style="font-family:宋体">.(</span>2019·</strong><strong><span style="font-family:宋体">云南初三期末)</span></strong><span style="font-family:宋体">中华诗词蕴含着丰富的物理知识,以下诗词中有关物态变化的分析,正确的是( )</span></p><p style="line-height: 150%;vertical-align: middle">A<span style="font-family:宋体">.</span><span style="font-family:宋体">“斜月沉沉藏海雾”,雾的形成是汽化现象,需要吸热</span></p><p style="line-height: 150%;vertical-align: middle">B<span style="font-family:宋体">.</span><span style="font-family:宋体">“已是悬崖百丈冰”,冰的形成是凝华现象,需要吸热</span></p><p style="line-height: 150%;vertical-align: middle">C<span style="font-family:宋体">.</span><span style="font-family:宋体">“露似真珠月似弓”,露的形成是液化现象,需要放热</span></p><p style="line-height: 150%;vertical-align: middle">D<span style="font-family:宋体">.</span><span style="font-family:宋体">“霜叶红于二月花”,霜的形成是凝固现象,需要放热</span></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:宋体;color:red">【答案】</span><span style="color:red">C</span></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:宋体;color:red">【解析】</span><span style=";color:red">A</span><span style="font-family:宋体;color:red">.</span><span style=";color:red">“</span><span style="font-family:宋体;color:red">斜月沉沉藏海雾</span><span style=";color:red">”</span><span style="font-family:宋体;color:red">,雾是空气中的水蒸气遇冷形成的小水珠,是液化现象,需要放热,故</span><span style=";color:red">A</span><span style="font-family:宋体;color:red">错误;</span></p><p style="line-height: 150%;vertical-align: middle"><span style=";color:red">B</span><span style="font-family:宋体;color:red">.</span><span style=";color:red">“</span><span style="font-family:宋体;color:red">已是悬崖百丈冰</span><span style=";color:red">”</span><span style="font-family:宋体;color:red">,冰是水凝固形成的,是凝固现象,需要放热,故</span><span style=";color:red">B</span><span style="font-family:宋体;color:red">错误;</span></p><p style="line-height: 150%;vertical-align: middle"><span style=";color:red">C</span><span style="font-family:宋体;color:red">.</span><span style=";color:red">“</span><span style="font-family:宋体;color:red">露似真珠月似弓</span><span style=";color:red">”</span><span style="font-family:宋体;color:red">,露的形成是液化现象,需要放热,故</span><span style=";color:red">C</span><span style="font-family:宋体;color:red">正确;</span></p><p style="line-height: 150%;vertical-align: middle"><span style=";color:red">D</span><span style="font-family:宋体;color:red">.</span><span style=";color:red">“</span><span style="font-family:宋体;color:red">霜叶红于二月花</span><span style=";color:red">”</span><span style="font-family:宋体;color:red">,霜是空气中的水蒸气遇冷形成的小冰晶,是凝华现象,凝华放热,故</span><span style=";color:red">D</span><span style="font-family:宋体;color:red">错误。</span></p><p style="line-height: 150%;vertical-align: middle"><strong>2</strong><strong><span style="font-family:宋体">.(</span>2019·</strong><strong><span style="font-family:宋体">湖南初二期末)</span></strong><span style="font-family:宋体">如图所示,在一敞口玻璃瓶甲里盛适量的水,使之能浮在一水槽中,将另一只同样的敞口空玻璃瓶乙瓶口朝下,按入槽内水中,并固定位置。在标准大气压下,对槽内水加热到沸腾时( )</span></p><p style="line-height: 150%;vertical-align: middle"><img width="65" height="98" src="http://www.czwlzx.com/UEditor/themes/default/images/spacer.gif" alt="学科网(www.zxxk.com)--教育资源门户,提供试题试卷、教案、课件、教学论文、素材等各类教学资源库下载,还有大量丰富的教学资讯!" style="background:url(http://www.czwlzx.com/UEditor/themes/default/images/word.gif) no-repeat center center;border:1px solid #ddd" /></p><p style="line-height: 150%;vertical-align: middle">A<span style="font-family:宋体">.</span><span style="font-family:宋体">甲、乙瓶中水都能沸腾 </span>B<span style="font-family:宋体">.</span><span style="font-family:宋体">甲瓶内水不沸腾,乙瓶内水沸腾</span></p><p style="line-height: 150%;vertical-align: middle">C<span style="font-family:宋体">.</span><span style="font-family:宋体">甲瓶内水沸腾,乙瓶内水不沸腾 </span>D<span style="font-family:宋体">.</span><span style="font-family:宋体">甲、乙瓶中水都不能沸腾</span></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:宋体;color:red">【答案】</span><span style="color:red">D</span></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:宋体;color:red">【解析】</span><span style="font-family:宋体;color:red">因为水在标准大气压下的沸点是</span><span style="font-family:'Times New Romance','serif';color:red">100℃</span><span style="font-family:宋体;color:red">,所以槽中水沸腾时温度是</span><span style="font-family:'Times New Romance','serif';color:red">100℃</span><span style="font-family:宋体;color:red">,并保持不变。甲瓶中水从槽内水中吸热,温度升高直到</span><span style="font-family:'Times New Romance','serif';color:red">100℃</span><span style="font-family:宋体;color:red">,这样甲瓶中的水温也能达到沸点,不过甲瓶中的水一旦与槽内的水温度相等,甲瓶中的水就无法吸热,当然不能沸腾。虽然乙瓶中水温同样可达到</span><span style="font-family:'Times New Romance','serif';color:red">100℃</span><span style="font-family:宋体;color:red">,但乙瓶上端封闭,瓶内气压大于标准大气压。因为液体沸点随液面上气压的增大而增大,所以乙瓶中水的沸点高于</span><span style="font-family:'Times New Romance','serif';color:red">100℃</span><span style="font-family:宋体;color:red">。这样乙瓶中水温达不到沸点,不能沸腾。故</span><span style="font-family:'Times New Romance','serif';color:red">D</span><span style="font-family:宋体;color:red">正确。</span></p><p style="line-height: 150%;vertical-align: middle"><strong>3</strong><strong><span style="font-family:宋体">.(</span>2019·</strong><strong><span style="font-family:宋体">仪征市第三中学初二期末)</span></strong><span style="font-family:宋体">如图是在探究甲、乙两种物质质量跟体积关系时作出的图像。则以下分析正确的是( )</span></p><p style="line-height: 150%;vertical-align: middle"><img width="169" height="106" src="http://www.czwlzx.com/UEditor/themes/default/images/spacer.gif" alt="学科网(www.zxxk.com)--教育资源门户,提供试题试卷、教案、课件、教学论文、素材等各类教学资源库下载,还有大量丰富的教学资讯!" style="background:url(http://www.czwlzx.com/UEditor/lang/zh-cn/images/localimage.png) no-repeat center center;border:1px solid #ddd" /></p><p style="line-height: 150%;vertical-align: middle">A<span style="font-family:宋体">.</span><em>ρ</em><sub><span style="font-family:宋体">甲</span></sub>><em>ρ</em><sub><span style="font-family:宋体">乙</span></sub> B<span style="font-family:宋体">.</span><em>ρ</em><sub><span style="font-family:宋体">甲</span></sub>< <em>ρ</em><sub><span style="font-family:宋体">乙 </span></sub>C<span style="font-family:宋体">.</span><em>V</em><sub><span style="font-family:宋体">甲</span></sub>><em>V</em><sub><span style="font-family:宋体">乙</span></sub> D<span style="font-family:宋体">.</span><em>m</em><sub><span style="font-family:宋体">甲</span></sub>=<em>m</em><sub><span style="font-family:宋体">乙</span></sub></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:宋体;color:red">【答案】</span><span style="color:red">A</span></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:宋体;color:red">【解析】</span><span style="font-family:'Times New Romance','serif';color:red">AB</span><span style="font-family:宋体;color:red">.由图可知,当两物体的体积相同时,甲的质量大,根据</span><span style="color:red"><img width="44" height="41" src="http://www.czwlzx.com/UEditor/themes/default/images/spacer.gif" alt="学科网(www.zxxk.com)--教育资源门户,提供试题试卷、教案、课件、教学论文、素材等各类教学资源库下载,还有大量丰富的教学资讯!" style="background:url(http://www.czwlzx.com/UEditor/themes/default/images/word.gif) no-repeat center center;border:1px solid #ddd" /></span><span style="font-family:宋体;color:red">可知,甲的密度大,</span><span style="color:red"><br /></span><span style="font-family:宋体;color:red">故</span><span style="font-family:'Times New Romance','serif';color:red">A</span><span style="font-family:宋体;color:red">正确、</span><span style=";color:red">B</span><span style="font-family:宋体;color:red">错误;</span></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:'Times New Romance','serif';color:red">CD</span><span style="font-family:宋体;color:red">.题中没有给出甲乙的质量和体积,所以无法进行比较,故</span><span style="font-family: 'Times New Romance','serif';color:red">CD</span><span style="font-family:宋体;color:red">错误。</span></p><p style="line-height: 150%;vertical-align: middle"><strong>4</strong><strong><span style="font-family:宋体">.(</span>2019·</strong><strong><span style="font-family:宋体">湖南初二期末)</span></strong><span style="font-family:宋体">关于物理测量仪器的使用,下列说法正确的是( )</span></p><p style="line-height: 150%;vertical-align: middle">A<span style="font-family:宋体">.</span><span style="font-family:宋体">零刻度线缺失的刻度尺不能用来测量物体的长度</span></p><p style="line-height: 150%;vertical-align: middle">B<span style="font-family:宋体">.</span><span style="font-family:宋体">使用天平测质量时,一定要等指针静止并在分度盘的中央时横梁才算平衡</span></p><p style="line-height: 150%;vertical-align: middle">C<span style="font-family:宋体">.</span><span style="font-family:宋体">所有液体温度计都不能拿离人体读数</span></p><p style="line-height: 150%;vertical-align: middle">D<span style="font-family:宋体">.</span><span style="font-family:宋体">用塑料卷尺测量长度时,若用力拉尺进行测量,那么由此将可能引起测量结果偏小</span></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:宋体;color:red">【答案】</span><span style="color:red">D</span></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:宋体;color:red">【解析】</span><span style="font-family:'Times New Romance','serif';color:red">A</span><span style="font-family:宋体;color:red">.刻度尺使用时可以从整刻度开始,零刻度线缺失的刻度尺也能用来测量物体的长度;故</span><span style="font-family:'Times New Romance','serif';color:red">A</span><span style="font-family:宋体;color:red">错误;</span></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:'Times New Romance','serif';color:red">B</span><span style="font-family:宋体;color:red">.当天平指针两边偏转程度相同时,认为天平平衡可以测量天平质量;故</span><span style="font-family:'Times New Romance','serif';color:red">B</span><span style="font-family:宋体;color:red">错误;</span></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:'Times New Romance','serif';color:red">C</span><span style="font-family:宋体;color:red">.体温计是液体温度计,它可以离开人体后再读数;故</span><span style="font-family: 'Times New Romance','serif';color:red">C</span><span style="font-family:宋体;color:red">错误;</span></p><p style="line-height: 150%;vertical-align: middle"><span style="font-family:'Times New Romance','serif';color:red">D</span><span style="font-family:宋体;color:red">.塑料卷尺本身具有一定的伸缩性,当我们用力拉尺进行测量时,读数会比实际读数偏小;故</span><span style="font-family:'Times New Romance','serif';color:red">D</span><span style="font-family:宋体;color:red">正确。</span></p><p><br /></p>北师大版不限试题试卷专供vip会员doc
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