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21542019年秋沪科版八年级物理上册教案:第五章 质量与密度 知识专题复习99.50KB99.50Bdocczwlzx吴晓娟czwlzx/UploadFiles/UserPic/UserAvatars/15219_150_150.jpg
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专题一 质量与密度的综合计算探究引路【例1】测出一个质量为6 g的金戒指的体积是0.32 cm3,它是否是纯金的专题一 质量与密度的综合计算探究引路【例1】测出一个质量为6 g的金戒指的体积是0.32 cm3,它是否是纯金的呢?(ρ金=19.3 g/cm3)解析 鉴别物质与判断物体空心、实心问题,可以从比较密度、比较质量、比较体积3个方面分析,根据题意灵活计算。答案 解法一:戒指的密度ρ===18.75 g/cm3,因为ρ<ρ金,所以戒指不是纯金制成的。解法二:假设戒指是由纯金制成的。所以其体积V金===0.31 cm3,因为V金<V,所以戒指不是纯金制成的。解法三:假设戒指是由纯金制成的。所以其质量m金=ρ金V=19.3 g/cm3×0.32 cm3=6.176 g,因为,m金>m,即戒指不是由纯金制成的。归纳拓展质量和密度是中考考查的一个重点内容。综合运用质量和密度的知识,
【内容简介】专题一 质量与密度的综合计算探究引路【例1】测出一个质量为6 g的金戒指的体积是0.32 cm3,它是否是纯金的呢?(ρ金=19.3 g/cm3)解析 鉴别物质与判断物体空心、实心问题,可以从比较密度、比较质量、比较体积3个方面分析,根据题意灵活计算。答案 解法一:戒指的密度ρ===18.75 g/cm3,因为ρ<ρ金,所以戒指不是纯金制成的。解法二:假设戒指是由纯金制成的。所以其体积V金===0.31 cm3,因为V金m,即戒指不是由纯金制成的。归纳拓展质量和密度是中考考查的一个重点内容。综合运用质量和密度的知识,可以算出一些无法直接测量的物理量,如物体的质量或体积;还可以根据密度判断所求物质是什么物质、物质的纯度、是否空心(如零件中是否含有气泡),以及计算混合物中各种物质的含量等。在学习中尤其要重视和实际生活相联系的题目。迁移应用1.一块纪念碑由大理石凿成,体积为50 m3。为了计算它的质量,现取一块纪念碑大理石样品,测出它的质量为140 g。用量筒装入200 mL的水,然后将这块样品浸没在水中,此时水面升高到250 mL。请你用这些数据,算出这块石碑的质量。专题一 质量与密度的综合计算探究引路【例1】测出一个质量为6 g的金戒指的体积是0.32 cm3,它是否是纯金的呢?(ρ金=19.3 g/cm3)解析 鉴别物质与判断物体空心
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2019年秋沪科版八年级物理上册教案(共28份)
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下载地址1|ja/2019/9/201992053957.doc<p style="text-indent:28px;line-height:150%">专题一 质量与密度的综合计算</p><p style="text-indent:28px;line-height:150%">探究引路</p><p style="text-indent:28px;line-height:150%"><span style="font-family:黑体">【例</span><span style="font-family:'Times New Roman','serif'">1</span><span style="font-family:黑体">】</span>测出一个质量为<span style="font-family:'Times New Roman','serif'">6 g</span>的金戒指的体积是<span style="font-family:'Times New Roman','serif'">0.32 cm<sup>3</sup></span><span style="font-family:'MingLiU_HKSCS','serif'">,</span>它是否是纯金的呢?<span style="font-family:'Times New Roman','serif'">(</span><em>ρ</em><sub>金</sub>=<span style="font-family:'Times New Roman','serif'">19.3 g/cm<sup>3</sup>)</span></p><p style="text-indent:28px;line-height:150%"><span style="font-family:黑体">解析</span><span style="font-family:楷体_GB2312"> 鉴别物质与判断物体空心、实心问题</span><span style="font-family:'MingLiU_HKSCS','serif'">,</span><span style="font-family:楷体_GB2312">可以从比较密度、比较质量、比较体积</span><span style="font-family:'Times New Roman','serif'">3</span><span style="font-family:楷体_GB2312">个方面分析</span><span style="font-family:'MingLiU_HKSCS','serif'">,</span><span style="font-family:楷体_GB2312">根据题意灵活计算。</span></p><p style="text-indent:28px;line-height:150%"><span style="font-family:黑体">答案</span> 解法一:戒指的密度<em>ρ</em>===</p><p style="text-indent:28px;line-height:150%"><span style="font-family:'Times New Roman','serif'">18</span><span style="font-family:'MingLiU_HKSCS','serif'">.</span><span style="font-family:'Times New Roman','serif'">75 g/cm<sup>3</sup></span><span style="font-family:'MingLiU_HKSCS','serif'">,</span></p><p style="text-indent:28px;line-height:150%">因为<em>ρ</em><span style="font-family:'Times New Roman','serif'"><</span><em>ρ</em><sub>金</sub><span style="font-family: 'MingLiU_HKSCS','serif'">,</span>所以戒指不是纯金制成的。</p><p style="text-indent:28px;line-height:150%">解法二:假设戒指是由纯金制成的。</p><p style="text-indent:28px;line-height:150%">所以其体积<em><span style="font-family:'Times New Roman','serif'">V</span></em><sub>金</sub>===<span style="font-family:'Times New Roman','serif'">0.31 cm<sup>3</sup></span><span style="font-family:'MingLiU_HKSCS','serif'">,</span></p><p style="text-indent:28px;line-height:150%">因为<em><span style="font-family:'Times New Roman','serif'">V</span></em><sub>金</sub><span style="font-family:'Times New Roman','serif'"><<em>V</em></span><span style="font-family:'MingLiU_HKSCS','serif'">,</span>所以戒指不是纯金制成的。</p><p style="text-indent:28px;line-height:150%">解法三:假设戒指是由纯金制成的。</p><p style="text-indent:28px;line-height:150%">所以其质量<em><span style="font-family:'Times New Roman','serif'">m</span></em><sub>金</sub>=<em><span style="font-family:'Times New Roman','serif'">ρ</span></em><sub>金</sub><em><span style="font-family:'Times New Roman','serif'">V</span></em>=<span style="font-family:'Times New Roman','serif'">19.3 g/cm<sup>3</sup></span>×<span style="font-family:'Times New Roman','serif'">0.32 cm<sup>3</sup></span>=</p><p style="text-indent:28px;line-height:150%"><span style="font-family:'Times New Roman','serif'">6</span><span style="font-family:'MingLiU_HKSCS','serif'">.</span><span style="font-family:'Times New Roman','serif'">176 g</span><span style="font-family:'MingLiU_HKSCS','serif'">,</span></p><p style="text-indent:28px;line-height:150%">因为<span style="font-family:'MingLiU_HKSCS','serif'">,</span><em><span style="font-family:'Times New Roman','serif'">m</span></em><sub>金</sub><span style="font-family:'Times New Roman','serif'">><em>m</em></span><span style="font-family:'MingLiU_HKSCS','serif'">,</span>即戒指不是由纯金制成的。</p><p style="text-indent:28px;line-height:150%">归纳拓展</p><p style="text-indent:28px;line-height:150%">质量和密度是中考考查的一个重点内容。综合运用质量和密度的知识<span style="font-family:'MingLiU_HKSCS','serif'">,</span>可以算出一些无法直接测量的物理量<span style="font-family:'MingLiU_HKSCS','serif'">,</span>如物体的质量或体积;还可以根据密度判断所求物质是什么物质、物质的纯度、是否空心<span style="font-family:'Times New Roman','serif'">(</span>如零件中是否含有气泡<span style="font-family:'Times New Roman','serif'">)</span><span style="font-family: 'MingLiU_HKSCS','serif'">,</span>以及计算混合物中各种物质的含量等。在学习中尤其要重视和实际生活相联系的题目。</p><p style="text-indent:28px;line-height:150%">迁移应用</p><p style="text-indent:28px;line-height:150%"><span style="font-family:'Times New Roman','serif'">1</span><span style="font-family:'MingLiU_HKSCS','serif'">.</span>一块纪念碑由大理石凿成<span style="font-family:'MingLiU_HKSCS','serif'">,</span>体积为<span style="font-family:'Times New Roman','serif'">50 m<sup>3</sup></span>。为了计算它的质量<span style="font-family: 'MingLiU_HKSCS','serif'">,</span>现取一块纪念碑大理石样品<span style="font-family:'MingLiU_HKSCS','serif'">,</span>测出它的质量为<span style="font-family:'Times New Roman','serif'">140 g</span>。用量筒装入<span style="font-family:'Times New Roman','serif'">200 mL</span>的水<span style="font-family:'MingLiU_HKSCS','serif'">,</span>然后将这块样品浸没在水中<span style="font-family:'MingLiU_HKSCS','serif'">,</span>此时水面升高到<span style="font-family:'Times New Roman','serif'">250 mL</span>。请你用这些数据<span style="font-family:'MingLiU_HKSCS','serif'">,</span>算出这块石碑的质量。</p><p><br /></p>沪科版不限教案专供vip会员doc
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